please answer by solving please
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<A=2x, <B = 3x
<ACD = I50
<BCD = I80
<BCD-<ACD = 180-150
<ACB= 30
Sum of the angles in a triangle = 150
<A+<B+<C=180
<ACB+2x + 3x=180
5X=I80-30
5X=150
X=150/5
x=30
4) c.1.2
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