Math, asked by lad1, 1 year ago

Please answer circled questions immediately i have to go tell these questions

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Answers

Answered by AshmitJain3107
1
(ii) In the first match he scored 64 runs.
So, in the second match he scored 64 + 12.5% of 64.
64 + 12.5/100 × 64
= 64 + 1/8 × 64
= 64 + 8
= 72.
In the third match he scored 72 - 12.5% of 72.
72 - 12.5/100 × 72
= 72 - 1/8 × 72
= 72 - 9
= 63.
Therefore, in the second match he scored 72 runs and in the third match he scored 62 runs.
(iii)Price of the toy in January = ₹75.
In February =
75 + 20/100 × 75
= 75 + 1/5 × 75
= 75 + 15
= ₹80
Price in March =
87 - 20/100 × 87
=87 - 1/5 × 87
=87 - 17.4
= ₹69.6
Ans 8)
Let the original price be x.
Then,
New price =
x + 100
Then,
x + 25x/ 100 = x + 100
x + x/4 = x + 100
(4x + x)/4 = x + 100
5x = 4*(x + 100)
5x = 4x+ 400
5x - 4x = 400
x = ₹400
Now the new price will be
400 + 100 = ₹500.
Please mark as brainliest if it helps you...

lad1: And 7 questions also please solve it hurry
AshmitJain3107: Why did u selected the wrong answer as brainliest??
lad1: Answer is right
lad1: 7 question solve kardo
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