Question

please answer class 12 chemistry ​

Answer 1

∆T=1.5K

K=3.9K kg mol-1

Mass of solvent=75g

Molar mass of solute=176.12g

molality (m)

=moles of solute/mass of solvent (kg)

=Weight (solute)/molar mass (solute)×0.075

=Weight (solute)/176.12×0.075

=Weight (solute)/13.209

∆Tf=Kb×m

∆Tf=Kb×Weight (solute)/13.209

Weight (solute)=1.5×13.209/3.9

Weight (solute)=5.08g

I hope this helps ( ╹▽╹ )