Question

Sameer's family went on a foreign trip. The currency of the country of their trip is not rupees but dollars. Sameer bought dollars in exchange of rupees for spending on the trip at the rate of Rs 70 for one dollar. After coming back to India, Sameer calculated that he is left with 1/10 of the dollars bought by him initially. He sold the dollars in exchange of rupees at 9/10 of the price at which he bought the dollar and got back Rs 21000. How many dollars had he bought initially? 


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Answer 1

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Answer 2

Solution :-

Let us Assume that sameer bought x Dollars initially .

So,

→ Total Money he Spend on x dollars = 70 * x = Rs.70x

Now, After coming back to India, Sameer calculated that he is left with 1/10 of the dollars bought by him initially.

So,

→ sameer Left with = x * (1/10) = (x/10) dollars.

Now, it is Given That, He sold the dollars in exchange of rupees at 9/10 of the price at which he bought the dollar.

And, we know That, he bought at the price of Rs.70/dollar.

So,

→ He sold The dollars at = (9/10) * 70 = Rs.63 / dollar.

So,

→ Money He got back for (x/10) dollars = (x/10) * 63 = Rs.(63x/10).

And, it is given that, he got Back Rs.21000.

Hence,

→ (63x/10) = 21000

→ 63x = 21000 * 10

Dividing Both sides by 21 ,

→ 3x = 10000

→ x = (10000/3) = 3333(1/3) Dollars . (Ans).

Hence, Sameer bought 3333(1/3) Dollars initially ...