Question

please answer correct with method I will Mark answer brainliest

construct a ∆ABC, given that BC = 6.5 CM, AC = 5 CM, and m∠C = 60°
write the steps of construction ​​​

Answer 1

Answer:

The ΔA

′

BC

′

whose sides are

4

3

of the corresponding sides of ΔABC can be drawn as follows:

Step 1: Draw a ΔABC with side BC=6cm,AB=5cm,∠ABC=60

∘

Step 2: Draw a ray BX making an acute angle with BC on the opposite side of vertex A.

Step 3: Locate 4 points, B

1

,B

2

,B

3

,B

4

on line segment BX.

Step 4: Join B

4

C and draw a line through B

3

, parallel to B

4

C intersecting BC at C

′

.

Step 5: Draw a line through C

′

parallel to AC intersecting AB at A

′

.

The triangle A

′

BC

′

is the required triangle.