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log 8 = log 2³ = 3 log 2 [ log m^n = n log m ]
log 9 = log 3² = 2 log 3
log 27 = log 3³ = 3 log 3
therefore the given problem reduces t
(3 log 2 × 2 log 3)/3 log 3
=> 3 log 2 × 2/3 [ log 3 cancels out ]
=> 2 log 2
=> log 4
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