Question

Please answer correctly​

Answer 1

Answer:

log 8 = log 2³ = 3 log 2 [ log m^n = n log m ]

log 9 = log 3² = 2 log 3

log 27 = log 3³ = 3 log 3

therefore the given problem reduces t

(3 log 2 × 2 log 3)/3 log 3

=> 3 log 2 × 2/3 [ log 3 cancels out ]

=> 2 log 2

=> log 4