please answer correctly
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Answer:
Step-by-step explanation:
[4x^2]+[1/9y^2] +[4x/3y ]-[ 4x^2] -[1/9y^2]+[4x/3y]
= 4x/3y + 4x/3y
= 8x/3y
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Step-by-step explanation:
[2x+1/3y]^2-(2x-1/3y)^2
(2x)^2+(1/3y)^2+2×2x×1/3y-[(2x)^2+(-1/3y)+2×2x×-1/3y]
4x^2+1/9y^2+4x/3y-[4x^2+1/9y^2-4x/3y]
4x^2+1/9y^2+4x/3y-4x^2-1/9y^2+4x/3y
4x/3y+4x/3y
8x/3y
it is Ur answer
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