Physics, asked by mathewjoseph3831v, 1 month ago

please answer correctly high points will be given​

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Answered by ramkrishnanj10
1

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 \tt{magnitude \: of \: resultant \: vector,}  \\  \\ \tt{ R =  \sqrt{ {A}^{2}  +  {B}^{2}  + 2ABcos\theta}}  \\  \\  \tt{direction \: of \: resultant \: vector} \\  \\  \tt{tan \alpha =  \frac{Asin \theta}{B + Acos\theta} }

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