Question

60 ml, 11.2 V H.0, sample is oxidised by 0.1 M KMnO, and 0.1 MK Cr.0, solution in acidic medium separately then. (A) volume of KMnO, used is more than K,Cr.o. (B) volume of KMnO, used is less than K Cr,O, (C) volume of KMnO, used is equal to K.Cr.O, (D) Can not be calculated.​

Answer 1

Answer:

Correct option is

B

more by K

2

CrO

7

Cr changes from +6 to +3 oxidation state on reduction. But there are two Cr atoms per molecule, net change is 2×3=6.

Mn changes from +7 to +2 on reduction. So, change is 5.

Hence, for equal molar and volume solutions of K

2

CrO

7

and KMnO

4

, more oxidation occurs from K

2

CrO

7

.