Physics, asked by samriddhi4285, 6 months ago

please answer fast .​

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Answered by Achyutaks
1

Answer:

g=Gm1/r^2

=(6.67×10^-11×2×10^27)/(7.14×10^7)^2

=(13.34×10^16)/(50.98×10^14)

=26.1 m/sec^2

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Answered by Thatsomeone
3

Explanation:

\sf Mass\:of\:Jupiter\:(M) = 2 × {10}^{27} \:kg \\ \sf Radius \:of\:Jupiter \:(R) = 7.14 × {10}^{7} \:m \\ \sf G = 6.67 × {10}^{-11} \:N{m}^{2}/kg \\ \\ \sf We\:know\:that \\ \\ \sf g = \frac{GM}{{R}^{2}} \\ \\ \sf \longrightarrow g = \frac{ 6.67 × {10}^{-11} × 2 × {10}^{27}}{{(7.14×{10}^{7})}^{2}} \\ \\ \sf \longrightarrow g = 0.2617 × {10}^{2} \\ \\ \sf \longrightarrow g = 26.17 \: m {s}^{-2}

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