Question

Please answer fast.. 30 points

Answer 1

sum of zeroes = m+n = - b/a
Product of zeroes = mn = c/a

(root m/n + root n/m) ^2 = m/n + n/m + 2*1
So m/n + n/m + 2 = (m^2 + n^2 + 2mn) /mn = (m+n) ^2/mn = (-b/a)^2/c/a =
b^2/ac
Then root of b^2/ac = b/root ac
is the answer

Answer 2

Answer:

sum of zeroes = m+n = - b/a

Product of zeroes = mn = c/a

(root m/n + root n/m) ^2 = m/n + n/m + 2*1

So m/n + n/m + 2 = (m^2 + n^2 + 2mn) /mn = (m+n) ^2/mn = (-b/a)^2/c/a =

b^2/ac

Then root of b^2/ac = b/root ac

is the answer