Please answer fast.. 30 points
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sum of zeroes = m+n = - b/a
Product of zeroes = mn = c/a
(root m/n + root n/m) ^2 = m/n + n/m + 2*1
So m/n + n/m + 2 = (m^2 + n^2 + 2mn) /mn = (m+n) ^2/mn = (-b/a)^2/c/a =
b^2/ac
Then root of b^2/ac = b/root ac
is the answer
Product of zeroes = mn = c/a
(root m/n + root n/m) ^2 = m/n + n/m + 2*1
So m/n + n/m + 2 = (m^2 + n^2 + 2mn) /mn = (m+n) ^2/mn = (-b/a)^2/c/a =
b^2/ac
Then root of b^2/ac = b/root ac
is the answer
annukumari21:
plzz confirm the answer
10th
hmm
no, answer is - root b/a
Answered by
0
Answer:
sum of zeroes = m+n = - b/a
Product of zeroes = mn = c/a
(root m/n + root n/m) ^2 = m/n + n/m + 2*1
So m/n + n/m + 2 = (m^2 + n^2 + 2mn) /mn = (m+n) ^2/mn = (-b/a)^2/c/a =
b^2/ac
Then root of b^2/ac = b/root ac
is the answer
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