Question

please ANSWER fast ................

Answer 1

hey dear friend here's ur answer :-)

if x=3+√8

$let \: \frac{1}{x} = \frac{1}{3 + \sqrt{8} } \times \frac{3 - \sqrt{8} }{3 - \sqrt{8} } \\ \\ \frac{3 - \sqrt{8} }{(3) {}^{2} - ( \sqrt{8} {}^{2} ) } = \frac{3 - \sqrt{8} }{9 - 8} = 3 - \sqrt{8} \\ \\ now \: .x + \frac{1}{x} = (3 + \sqrt{8} ) + (3 - \sqrt{8} ) \\ \\ = 3 + 3 = 6 \\ \\ (x + \frac{1}{x}) {}^{2} = x {}^{2} + \frac{1}{x} {}^{2} + 2 \times x \times \frac{1}{x} \\ \\ (6) {}^{2} = x + \frac{1}{x} + 2 \\ \\ x + \frac{1}{x} = 36 - 2 \\ \\ x + \frac{1}{x} = 34$


hope it helps :-)