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let h be the height of the tree.
in triangleABC,
tan30° = h / x
1/ √3 = h/ x => h = x/√3---(1)
in triangle ABD,
tan60° = h / (x - 40)
√3 = h/ ( x - 40)
√3 = (x/√3) /( x - 40)
√3 = x/√3 ( x - 40)
x = √3 × √3( x - 40)
x = 3x - 120 => 2x = 120
x = 60m
from(1) h = x/ √3
= 60/√3 =(60×√3)/(√3 ×√3)
= 60√3/ 3 = 20√3
= 20×1.73 = 34.6m
height of the tree = 34.6m
width of the river = x - 40
= 60 - 40 = 20m
Answer:
height of the tree = 34.6m, and width of the river = 20m
in triangleABC,
tan30° = h / x
1/ √3 = h/ x => h = x/√3---(1)
in triangle ABD,
tan60° = h / (x - 40)
√3 = h/ ( x - 40)
√3 = (x/√3) /( x - 40)
√3 = x/√3 ( x - 40)
x = √3 × √3( x - 40)
x = 3x - 120 => 2x = 120
x = 60m
from(1) h = x/ √3
= 60/√3 =(60×√3)/(√3 ×√3)
= 60√3/ 3 = 20√3
= 20×1.73 = 34.6m
height of the tree = 34.6m
width of the river = x - 40
= 60 - 40 = 20m
Answer:
height of the tree = 34.6m, and width of the river = 20m
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