Question

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A hemispherical tank is made up of an iron sheet 1 cm thick. If the inner radius is 1 m, then find the volume of the iron used to make the tank.

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Answer 1

Answer:

PROCEDURE,

To find volume of iron required we have to find volume of inner hemisphere when we have to subtract it from volume of outer hemisphere.

As there is thickness also given so there will be two hemispheres of radius 1m

and 1.01m respectively .

volume of inner hemisphere

$V_1 = \frac{2}{3} \pi {r _{1} }^{3} \\ \\ = \frac{2}{3} \times \frac{22}{7} \times {1}^{3} \\ \\ = \frac{44}{21} {m}^{3}$

Volume of outer hemisphere:-

$V_2 = \frac{2}{3} \pi {r_2}^{3} \\ \\ = \frac{2}{3} \times \frac{22}{7} \times {(1.01)}^{3} \\ \\ = (\frac{44}{21} \times 1.030301) {m}^{3}$

Now,

volume of iron used to make the tank will be

$V = V_2 - V_1 \\ = \frac{44}{21} \times 1.030301 - \frac{44}{21} \\ \\ = \frac{44}{21} (1.030301 - 1) \\ \\ = \frac{44}{21} (0.030301) \\ \\ = (\frac{1.333244}{22} ) {m}^{3} \\ \\ = 0.060602 {m}^{3} \\ \\ = 6.0602 {cm}^{3}$

Answer 2

Answer:

Hello mate✌✌✌

Kindly refer to the attachment.

Hope it helps✌✌✌