Question

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Answer 1

Hello Friend....

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The answer of u r question is....

Ans:

In pQR,we have

$pr = \sqrt{ {pq}^{2} } - {qr}^{2}$

$= \sqrt{ ({29}^{2} }) - ( {21}^{2} )$

$\sqrt{400}$

$= 20 \: units$

$\sin( tita) = \frac{pr}{pq}$

$= \frac{20}{29}$

$\cos(tita) = \frac{qr}{pq} = \frac{21}{29}$

Now,

$1) {cos}^{2} tita + {sin}^{2} tita = ( \frac{21}{29} )sqare + \frac{20}{29} square$
$= \frac{441 + 400}{841} = 1$

$2) {cos}^{2} tita - {sin}^{2} tita = \frac{21}{29} square - \frac{20}{29} square$

$= \frac{41}{841}$

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Thank you....⭐️⭐️⭐️⭐️⭐️

Answer 2

Hye !!

Refer to the attachment !!