Question

please answer fast guys​

Answer 1

Answer:

Step-by-step explanation:

x=a(b-c),y=b(c-a) and z=c(a-b)

Now

x/a=b-c

y/b=c-a

z/c=a-b

so x/a+y/b+z/c=b-c+c-a+a-b=0

We know if x+y+z=0 then x³+y³+z³=3xyz

hence ( x/a)³+(y/b)³+(z/c)³=3*x/a*y/b*z/c= 3xyz/abc