Question

please answer fast I'm waiting ​

Answer 1

Step-by-step explanation:

AB^2 =BE^2+AE^2 - - - >1

AE^2+ED^2=AD^2 - - - - >2

AE^2+EC^2=AC^2 - - - - - >3

FROM 1 AND 3

AB^2 + AC^2= BE^2+AE^2+AE^2+EC^2

EC^2=(ED+DC)^2

ED^2+DC^2+2 ED DC

NOW

AB^2 + AC^2= BE^2+AE^2+AE^2+ED^2+DC^2+2 ED DC

AB^2 + AC^2= BE^2+AE^2+AE^2+ED^2+DC^2+2 ED DC +2 BE ED - 2BE ED

AB^2 + AC^2= BD^2+AE^2+AE^2+DC^2+2 ED DC - 2BE ED

REPLACE AE^2 FROM 2

AB^2 + AC^2= BD^2+ 2AD^2 -2ED^2+DC^2+2 ED DC - 2BE ED

ADD BD^2 AND SUB BD^2

AB^2 + AC^2= 2BD^2+ 2AD^2 -2ED^2+DC^2+2 ED DC - 2BE ED - (BE+ED) ^2

FROM HERE U CAN SOLVE

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Answer 2

Step-by-step explanation:

From ∆ADB,

According to Pythagoras theorem,

AB² = AD² + BD² ------ (1)

From ∆ADC ,

according to Pythagoras theorem,

AC² = AD² + DC²    ----- (2)

Given,  AD is median.

so,

BD = DC     ------- (3)

from equations (1) , (2) and (3),

AB² + AC² = AD² + AD² + BD² + BD²

AB² + AC² = 2(AD² + BD²)

Hope it helps!