Question

Please answer fast in copy​

Answer 1

Given :

• A Triangle with sides (2x+5), (3x-7) and (-x+11)

To Find :

• Perimeter of the Triangle

Solution :

We know that,

$\bigstar \: \boxed{ \sf \: Perimeter = Sum \: of \: all \: sides }$

$\longrightarrow \sf \: (2x + 5) + (3x - 7) + ( - x + 11)$

Remove the brackets

$\longrightarrow \sf \: 2x + 5 + 3x - 7 - x + 11$

Arrange the constants and variables

$\longrightarrow \sf \: 2x + 3x - x + 5 - 7 + 11$

Simplify

$\longrightarrow \sf \: 5x - x + 16 - 7$

Final Simplification

$\longrightarrow \sf \red{ 4x + 9}$

$\therefore$ Perimeter of the triangle is (4x+9) units

About Triangles :

• Triangle is a closed figure bounded by 3 line segments.

• There are 3 angles, 3 sides and 3 vertices of the triangle.

• Sum of all angles of Triangle is 180°

• Triangles are Divided on the basis of angles and side.

• On the basis of angle Triangles are classified into 3 parts.

• On the basis of side Triangles are classified into 3 parts too.

Answer 2

Given :-

• 1st side = 3x - 7
• 2nd side = -x + 11
• 3rd side = 2x + 5

To find :-

• Perimeter of the triangle

Formula used :-

• Perimeter of triangle = sum of all its side.

According to the question,

Perimeter of triangle = sum of all its side

= ( 3x - 7) + (-x + 11) + (2x + 5)

= 3x - 7 - x + 11 + 2x + 5

= 3x - x + 2x - 7 + 11 + 5 [Arrange the like terms]

= 5x - x + 4 + 5

= 4x + 9

.°. The answer is 4x + 9.