Math, asked by avni2801, 4 months ago

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Answers

Answered by Hridhee
0

1 Simplify 1\times 2b1×2b to 2b2b.

{0}^{2}b(a-{h}^{2})+a{b}^{2}(4ab-2{a}^{2})-{a}^{3}b\times 2b0

2

b(a−h

2

)+ab

2

(4ab−2a

2

)−a

3

b×2b

2 Simplify {0}^{2}0

2

to 00.

0b(a-{h}^{2})+a{b}^{2}(4ab-2{a}^{2})-{a}^{3}b\times 2b0b(a−h

2

)+ab

2

(4ab−2a

2

)−a

3

b×2b

3 Simplify 0b(a-{h}^{2})0b(a−h

2

) to 00.

0+a{b}^{2}(4ab-2{a}^{2})-{a}^{3}b\times 2b0+ab

2

(4ab−2a

2

)−a

3

b×2b

4 Use Product Rule: {x}^{a}{x}^{b}={x}^{a+b}x

a

x

b

=x

a+b

.

0+a{b}^{2}(4ab-2{a}^{2})-{a}^{3}{b}^{2}\times 20+ab

2

(4ab−2a

2

)−a

3

b

2

×2

5 Regroup terms.

0+a{b}^{2}(4ab-2{a}^{2})-2{a}^{3}{b}^{2}0+ab

2

(4ab−2a

2

)−2a

3

b

2

6 Collect like terms.

a{b}^{2}(4ab-2{a}^{2})-2{a}^{3}{b}^{2}ab

2

(4ab−2a

2

)−2a

3

b

2

7 Expand by distributing terms.

4{a}^{2}{b}^{3}-2{a}^{3}{b}^{2}-2{a}^{3}{b}^{2}4a

2

b

3

−2a

3

b

2

−2a

3

b

2

8 Collect like terms.

4{a}^{2}{b}^{3}+(-2{a}^{3}{b}^{2}-2{a}^{3}{b}^{2})4a

2

b

3

+(−2a

3

b

2

−2a

3

b

2

)

9 Simplify.

4{a}^{2}{b}^{3}-4{a}^{3}{b}^{2}4a

2

b

3

−4a

3

b

2

Done

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