Math, asked by jatinrao2, 11 months ago

Please answer fast its urgent

Attachments:

Answers

Answered by digi18
1

2). Let the 2 digit no. Be 10x + y

x = 3y. Eq1

10y + x = 10x + y - 36

9y - 9x = 36

Take 9 common

y - x = 4. Eq2

Now put value of X in eq2

y - 3y = 4

y = - 4 / 2 = - 2

Now put value of y in eq1

x = 3y

x = 3*(-2) = - 6

Two digit no. Will be

10x + y

= 10(-6) + (-2)

= - 62

Thanks

Similar questions