Math, asked by jhyotshna, 7 days ago

please answer fast
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Answered by nishanetke478

0

Answer:

=3(cos4a+sin4-a)-2(cos6a+sin6a)

=3(1-2sin2acos2a)-2(1-2sin2acos2a)

=3-6sin2acos2a-2+6sin2acos2a=1

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