Question

please answer fast PLEASE​

Answer 1

Explanation:

(4/9)⁶×(4/9)-⁴

${a}^{m} \times {a}^{n} = {a}^{m + n}$

$( \frac{4}{9})^{2} \times( \frac{4}{9})^{ - 4} \\ = (\frac{4}{9} )^{2 - 4} \\ = (\frac{4}{9} )^{ - 2}$

Answer 2

(4/9)⁶×(4/9)-⁴

{a}^{m} \times {a}^{n} = {a}^{m + n}a

m

×a

n

=a

m+n

\begin{gathered}( \frac{4}{9})^{2} \times( \frac{4}{9})^{ - 4} \\ = (\frac{4}{9} )^{2 - 4} \\ = (\frac{4}{9} )^{ - 2}\end{gathered}