Math, asked by pranavlazar, 1 year ago

Please answer fast pleaseeeeer

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Answered by Anonymous
6

Answer:

Not similar .

Step-by-step explanation:

In Δ ABO ,

cos ∠AOB = BO/AO

⇒ cos ∠AOB = 9/16

Also in Δ COD ,

sin ∠ODC = OC/OD

⇒ sin∠ODC = 5/9

⇒ sin²∠ODC = 25/81

⇒ 1 - sin²∠ODC = ( 81 - 25 )/81

⇒ cos²∠ODC = 56/81

⇒ cos ∠ODC = √56/9

Hence none of the angles are equal .

In Δ ABO and Δ OCD ,

AO/AB = 16/9

DO/OC = 9/5

Hence AO/AB ≠ DO/OC

Thus none of the angles are equal as well as sides ratio is not equal .

∴ They are not similar triangles .


pranavlazar: Thanks
Answered by generalRd
3
In the given question

Answer =>No, they are not similar.


Refer to attachment also for some more information.

1)The two triangles are right angled traingled and both had only one similar angle of 90°

2)The sides of both the triangles are not in the similar ratio.

So we can use neither of the similarity criterion here as both the triamgles are not similar.

Thanks
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