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Answer:
Not similar .
Step-by-step explanation:
In Δ ABO ,
cos ∠AOB = BO/AO
⇒ cos ∠AOB = 9/16
Also in Δ COD ,
sin ∠ODC = OC/OD
⇒ sin∠ODC = 5/9
⇒ sin²∠ODC = 25/81
⇒ 1 - sin²∠ODC = ( 81 - 25 )/81
⇒ cos²∠ODC = 56/81
⇒ cos ∠ODC = √56/9
Hence none of the angles are equal .
In Δ ABO and Δ OCD ,
AO/AB = 16/9
DO/OC = 9/5
Hence AO/AB ≠ DO/OC
Thus none of the angles are equal as well as sides ratio is not equal .
∴ They are not similar triangles .
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In the given question
Answer =>No, they are not similar.
Refer to attachment also for some more information.
1)The two triangles are right angled traingled and both had only one similar angle of 90°
2)The sides of both the triangles are not in the similar ratio.
So we can use neither of the similarity criterion here as both the triamgles are not similar.
Thanks
Answer =>No, they are not similar.
Refer to attachment also for some more information.
1)The two triangles are right angled traingled and both had only one similar angle of 90°
2)The sides of both the triangles are not in the similar ratio.
So we can use neither of the similarity criterion here as both the triamgles are not similar.
Thanks
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