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answer of a is y=75°
x=65°
answer of b is x=75°
y=105°
z=35°
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In figure (a)
angle= ACD + ACB = 180°
= ACB = 180° - 115°
angle = ACB = 65°
ALSO ,
angle = CAB + B + ACB = 180°
= CAB = 180° - 105°
= CAB = 75°
In figure (b)
triangle ADC
45°+60°+x=180
x = 75°
Similarly,
angle = x+y = 180°
= y = 105°
Again,
In triangle ADB
angle= 105°+40°+z = 180°
=> z = 35°
I HOPE IT HELPS.
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