Question

(please answer fast with steps)

a tree is broken at height of 7m from the ground and its top touches the ground at distance of 12m from the base of the tree.find the original height of the tree
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Answer 1

Step-by-step explanation:

Answer

Let A'CB represents the tree before it broken at the point C and let the top A' touches the ground at A after it broke. Then ΔABC is a right angled triangle, right angled at B.

AB=12m and BC=5m

Using Pythagoras theorem, In ΔABC

(AC)

2

+(AB)

2

+(BC)

2

⇒(AC)

2

=(12)

2

+(5)

2

⇒(AC)

2

=144+25

⇒(AC)

2

=169

⇒AC=13m

Hence, the total height of the tree=AC+CB=13+5=18m.

Answer 2

Step-by-step explanation:

by using pythagorus theorem

hypotenuous = x m

height = 7 m

base= 12m

h2= p2+b2

7^2+12^2

49 +144

193

h=√193

h=13.9 m

therefore original height of tree =7+13.9

20.9m