Question

please answer find zeros of

Answer 1

√3x²-8x+4√3=0

√3x² - 6x-2x+4√3=0

√3x(x-2√3)-2(x-2√3)=0

(√3x-2) ( x-2√3)=0

x=2/√3 or x= 2√3

Answer 2

let p(x) =√3 x² -8x + 4√3
to find zeroes we have to take
p(x) =0
√3 x² -8x +4√3 =0
⇒√3x² -6x -2x + 4√3=0
⇒ √3 x² - 2*√3*√3 x - 2x+4√3=0
⇒√3 x( x-2√3) -2(x-2√3) =0
⇒(x-2√3) (√3x-2) =0
∴x-2√3 =0 or √3x -2=0
x= 2√3 or x= 2/√3
∴ zeroes are 2√3 or 2/√3