Question

please answer for this question ​

Answer 1

Answer:

Given,

ABC is a equalateral triangle

radius of circle is 32cm

Now,

pariwrit ki radius = multiply of sides

4(area of ∆)

32= a×a×a.

4×√3a²/4

32= a³.

4√3a²/4

32= a³×4.

4√3a²

32= a.

√3

32√3=a

ar of design= ar of circle - ar of triangle

= πr² - √3a²/4

= {3.14×(32)²}-{√3(32√3)²/4}

= (3.14×1024)-{(√3×1024×3)/4}

= 3215.36-(1.73×256×3)

= 3215.36 - 1328.64

= 1886.72

hence area of design is 1886.72

..........666......