Question

please answer friends ​

Answer 1

Hii its tom85

p(x)=x^5+3x^2+1

p(0)=0+0+1

p(0)=1

__________/\__________☺️

hope it may helps you dude

Answer 2

Step-by-step explanation:

P(x)= x5+3x²+1

therefore for P(0)... put x=0 at every place where x exists

i.e.

P(0)= (0)5+3(0)²+1

=0+0+1

P(0)= 1..

Hope it helps ....: )

plz mark brainliest....