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Find the 12th term from the end in A.P. 13 , 18 , 23 , ....
Find the sum of first 20 terms of the A.P. 5 , 8 , 11 , ......
If 6th and 17th terms of an A.P. are 19 and 52 respectively , then 10th term is
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- As we can see that from start everytime 5 is adding to the number. So, if we see from end we have to subtract 5 from the numbers till 12th term to get the number. By doing this our answer will be, 98
- Ans =670 A =5 first term of ap d =3 difference of a2 a1
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6th term = 19
17th term = 41
a+5d= 19
a+16d= 41
- -
- 11d= -22d
a + 5(2) = 19
a=19-10
a=9
hence, 40th term = a+39d
= a+39(2)
=9+78
= 87
Answer= 87.
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