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Let the function be represented by f(x).
As x+2, exactly divides f(x),
−2 is a zero of f(x), hence f(−2)=0
f(x)=2x3+5x2−x−k
f(−2)=2(−23)+5(−22)+2−k=0
⇒0=−16+20+2−k
⇒k=6
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