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HNO3
So H*1+N*1+O*3
1*1+14*1+16*3
1+14+48
63u is the molar mass of HNO3
Now, 27 g of aluminium contains 6.022*10^23 atoms
27*10=6.022×10×10^23
270g=6.022*10^24 atoms
So H*1+N*1+O*3
1*1+14*1+16*3
1+14+48
63u is the molar mass of HNO3
Now, 27 g of aluminium contains 6.022*10^23 atoms
27*10=6.022×10×10^23
270g=6.022*10^24 atoms
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