Question

"Please answer how to do this problem If two years ago, my mother's age was square of my age and if two years from now, it will be four times my age, what is my current age​

Answer 1

Step-by-step explanation:

2 yrs back:

my age= x

mother age= x²

after 2 yrs from now:

my age =4+x yrs

mother age = x²+4 yrs

or according to question:

mother age = 2* my age = 2*(4+x) yrs= 8+2x

EQ... 8+2x = x²+4

8-4 = x²-2x

4=x²-2x

here forms quadratic equation

x²-2x-4=0

then u can solve this.

if not then make another question because it's too lengthy.

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