Question

please answer

If a and b are positive real numbers then √ab=
​

Answer 1

Answer:

If a and b are positive real numbers, then a+b≥2ab−−√.

I know how to do the direct proof, but in this case, I want to try proving it by contradiction. I have tried manipulating the inequality a+b<2ab−−√ after making the assumption that a,b>0 to get a contadiction a,b≤0.

a+ba2−2ab+b2(a−b)2<2ab−−√<0<0,

Step-by-step explanation:

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