Question

Please answer
If the roots of
${2x}^{2} - 6x + k = 0$
are re and equal then find value of k​

Answer 1

Answer:

Step-by-step explanation:

2x2+6x+k=2(x−α)(x−β)=2x2−2(α+β)+2αβ  

α+β=−3

αβ=k/2

αβ+βα=α2+β2αβ=(α+β)2−2αβαβ=(α+β)2αβ−2=18k−2

Answer 2

✨✨Heyaaa✨✨

The solution is above in the attachment..

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