Question

please answer im confued

Answer 1

Don't worry friend HARSH is here....

Answer:

We know,

P(of an event)=No. of possibilities of the event/total no. of events

Now,

P(more than one assignment) =

= 5/18 + 1/3

=11/18

Answer 2

${\huge{\underline{\underline{\mathfrak{\red{Solution}}}}}}$

We know,

P ( of the event) = No. of possibilities of the total no. of the events .

Now ,

P (more than one assignment) =

= 5 / 18 + 1 / 3

= 11 / 18