Question

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Answer 1

Given :-

as shown in the figure p and q are two points on equal sides AB and AC of an isosceles traingle ABC.

To Prove :-

BQ = CP

SOLUTION:-

➪Thus, AB - AP = AC - AQ

➪Hence BP - CQ

➪Now the traingle BCP and BCQ ,

➪BP = CQ { Given}

➪angle B = angle C {ABC is an isosceles traingle}

and Bc is common.

➪Hence , traingle BCP and BCQ are congruent (two and the included angle to that of the other).

➪Therefore,BQ = CP which are opposite the equal angles B and C.

☞︎︎︎See the above attachment is the figure✔︎

Answer 2

Answer:

in this case you will have to prove these triangles congruent

Step-by-step explanation:

in triangle ABQ and ACP

angle A = angle A (common)

AP=AQ(given)

AB =AC (given)

therefore triangle ABQ is congruent toACP

therefore by cpct BQ = CP