solve 5x+y=20, 10x-2y=50 by substitution method pleas Koi solve kr do important
Answers
Basic Concept Used :-
To solve systems using substitution, follow this procedure:
- Select one equation and solve it to get one variable in terms of second variables.
- In the second equation, substitute the value of variable evaluated in Step 1 to reduce the equation to one variable.
- Solve the new equation to get the value of one variable.
- Substitute the value found in to any one of two equations involving both variables and solve for the other variable.
Let's solve the problem now!!
↝ Given Linear Equations are
and
↝ From equation (1), we have
↝ Substituting the value of y in equation (2),
↝ On substituting the value of x in equation (3), we get
Additional Information
There are 4 methods to solve this type of pair of linear equations.
- 1. Method of Substitution
- 2. Method of Eliminations
- 3. Method of Cross Multiplication
- 4. Graphical Method
Answer:
x = 9/2 and y = -5/2
Step-by-step explanation:
The given equations are :
5x + y = 20 ...(1)
10x - 2y = 50 ...(2)
From equation (1), we get;
5x + y = 20
5x = 20 -y
x = (20 - y)/5
Substituting x = (20 - y)/5 in equation (2), we get;
10 (20 - y)/5 - 2y = 50
(200 - 10y)/5 -2y = 50
(200 - 10y -10y)/5 = 50
200 - 20y = 50 x 5
200 - 20y = 250
-20y = 250 - 200
-20y = 50
y = 50/-20
y = -5/2
Substituting the value of y in equation (1), we get;
5x + y = 20
5x + (-5/2) = 20
5x - 5/2 = 20
(10x - 5)/2 = 20
10x - 5 = 20 x 2
10x - 5 = 40
10x = 40 + 5
10x = 45
x = 45/10
x = 9/2
Hope it helps u...