Question

please answer in details​

Answer 1

solve it by simplification easily

Answer 2

Answer:

2

Step-by-step explanation:

Correct option is

D

2

Given

(2x

3x−1

+10)÷7=6

7

(2x

3x−1

+10)

=6

Here we have to find the value of x

Now by cross multiplying the above equation we get (2x

3x−1

+10)=6×7

⇒(2x

3x−1

+10)=42

Now shift 10 to R.H.S it becomes −10

⇒(2x

3x−1

)=42−10=32

But we know that 2

5

=32

Substituting this to above equation we get

⇒(2x

3x−1

)=2

5

Since the base term in equation is same, according to laws of exponents we can equate them as

⇒3x−1=5

Now shift −1 to R.H.S we get

3x=5+1=6

3x=6

Now shift 3 to R.H.S

x=

3

6

=2

this can help you