Math, asked by aryangupta5475, 5 months ago

please answer it ....​

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Answers

Answered by tennetiraj86
1

Answer:

answer for the given problem is given

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Answered by gopalpvr
1

Step-by-step explanation:

(x^2-4)-(x+2(x-2)=0

x^2 - 4 - (x^2 - 4) = 0

x^2 - 4 - x^2 + 4 = 0

=0

even though you put X =0, 2, 3

(3a-2b)= 9

ab= 7

(3a - 2b)^2=9^2

9a^2 + 4 b^2 - 12ab=81

9a^2 + 4 b^2 - 12(7)=81

9a^2 + 4 b^2 - 84 = 81

9a^2 + 4 b^2 = 81 + 84

9a^2 + 4 b^2 = 165

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