Question

please answer it.... ​

Answer 1

I think so it is correct

Answer 2

GIVEN,

$\begin{tabular}{|c|c|} \cline{1-2}1&5 \\ \cline{1-2}2&9 \\ \cline{1-2}3&12 \\ \cline{1-2}4&17 \\ \cline{1-2}5&14 \\\cline{1-2}6&10 \\ \cline{1-2}7&6 \\ \cline{1-2} \end{tabular}$

Now we will find Fi which is product of frequency and variable.

$\begin{tabular}{|c|c|c|}\cline{1-3}Variable&Frequency&Fi \\ \cline{1-3}1&5&5 \\ \cline{1-3}2&9&18 \\ \cline{1-3}3&12&36 \\ \cline{1-3}4&17&68 \\ \cline{1-3}5&14&70 \\\cline{1-3}6&10&60 \\ \cline{1-3}7&6&42 \\ \cline{1-3} \end{tabular}$

Now, we will find the sum of all frequencies and Fi.

$\begin{tabular}{|c|c|c|}\cline{1-3}Variable&Frequency&Fi \\ \cline{1-3}1&5&5 \\ \cline{1-3}2&9&18 \\ \cline{1-3}3&12&36 \\ \cline{1-3}4&17&68 \\ \cline{1-3}5&14&70 \\\cline{1-3}6&10&60 \\ \cline{1-3}7&6&42 \\ \cline{1-3}Total&73&299 \\ \cline{1-3} \end{tabular}$

Now we will fine mean by formula,

$MEAN=\dfrac{ \Sigma FI}{\Sigma F}$

$MEAN=\dfrac{299}{73}$

MEAN = 4.09