please answer it as soon as possible
Answers
Answer:
sorry I didn't know how to do
Given : x + y + √3(y - x) = a
To Find : Equations of line passing through origin and inclined at 75°
Solution:
x + y + √3(y - x) = a
=> y ( √3 + 1) = x (√3 - 1) + a
=> y = x (√3 - 1) / ( √3 + 1) + a
m = (√3 - 1) / ( √3 + 1)
=> m = ( 1 - 1/√3 ) / ( 1 + 1/√3)
=> m = (tan π/4 - tan π/6) / ( 1 + tanπ/4 . tan π/6)
=> m = tan ( π/4 - π/6)
=> m = tan 15°
=> α = 15° inclined at 15°
inclined at 75°
=> 15° ± 75° = - 60° , 90°
tan - 60° = - √3
tan 90° = 1/0
y - y₁ = m (x - x₁)
passed through origin
Hence y = mx
=> y = - √3x
=> √3x + y = 0
y = (1/0)x
=> x = 0
√3x + y = 0 and x = 0 are the Equations of line passing through origin and inclined at 75°
Learn More:
if the pair of linear equations 2x+5y=7 and 4x+3y=b is consistent the ...
brainly.in/question/14932663
35.Which of the following pairs of equations are consistent?a. x+y ...
brainly.in/question/20731593