Question

please answer it fast

Answer 1

$a - b + a + a + b = \frac{p}{1} \\ 3a = p \\ (a - b)a + a(a + b) + (a + b)(a - b) = q \\ {a}^{2} - ab + {a}^{2} + ab + {a}^{2} - {b}^{2} = q \\ 3 {a}^{2} - {b}^{2} = q \\ \frac{ {p}^{2} }{3} - {b}^{2} = q \\ {b}^{2} = \frac{ {p}^{2} }{3} - q\\ (a - b)a(a + b) = r \\ a({a}^{2} - {b}^{2} ) = r \\ \frac{p}{3} ( \frac{ {p}^{2} }{9} - \frac{ {p}^{2} }{3} + q) = r \\ p( {p}^{2} - 3 {p}^{2} + 9q) = 27r \\ p( 9q - 2{p}^{2} ) = 27r \\ 2 {p}^{3} - 9pq + 27r = 0$