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Given f(x) = 4x^3 - 12x^2 + 14x - 3.
Given g(x) = x - 1/2.
By remainder theorem, g(x) = 0.
= > x - 1/2 = 0
= > x = 1/2.
Plug x = 1/2 in f(x), we get
= > 4(1/2)^3 - 12(1/2)^2 + 14(1/2) - 3
= > (1/2) - 3 + 7 - 3
= > (1/2) + 1
= > 3/2.
Hope this helps!
Given g(x) = x - 1/2.
By remainder theorem, g(x) = 0.
= > x - 1/2 = 0
= > x = 1/2.
Plug x = 1/2 in f(x), we get
= > 4(1/2)^3 - 12(1/2)^2 + 14(1/2) - 3
= > (1/2) - 3 + 7 - 3
= > (1/2) + 1
= > 3/2.
Hope this helps!
siddhartharao77:
:-)
But how did you get -3+7
12(1/2)^2 = 12(1/4) = 12/4 = 3. 14(1/2) = 14/2 = 7
Answered by
1
Hey!!
Given p(x) = 4x^3 - 12x^2 + 14x - 3
g (x) = x - 1/2
By remainder theorem
=> x - 1/2
=> x = 1/2
p (x) = 4 (1/2)^3 - 12 (1/2)^2 + 14 (1/2) - 3
=> 4 (1/8) - 12 (1/4) + 14/2 -3
=> 4/8 - 3 + 7 - 3
=> 1/2 + 1
=> 3/2.
__________________
Hope it will helps you:-)
Given p(x) = 4x^3 - 12x^2 + 14x - 3
g (x) = x - 1/2
By remainder theorem
=> x - 1/2
=> x = 1/2
p (x) = 4 (1/2)^3 - 12 (1/2)^2 + 14 (1/2) - 3
=> 4 (1/8) - 12 (1/4) + 14/2 -3
=> 4/8 - 3 + 7 - 3
=> 1/2 + 1
=> 3/2.
__________________
Hope it will helps you:-)
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