Math, asked by SANJAILION, 1 year ago

please answer it fast

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Answered by mrdeep
0
answer is
 {43}^{2}
as
 {1}^{2}  +  {2}^{2}  +  {2}^{2}  =  {3}^{2} \\ where \:  {1 + 2}^{2}  =  {3}^{2}  \\ so \: on \\ last {6}^{2}  +  {7}^{2}  +  {..}^{2}  =  {....}^{2} \\ here {..}^{2}  =  {42}^{2}  \\ and \\  {...}^{2}  =  {43}^{2}
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