Question

Please answer it fast I want the solution

Answer 1

For first body,
Using v^2-u^2=2aS
As it is dropped, u=0
v^2=2aS
v=3. (given)
9=2aS
S=9/2a. -(i)
For second body,
Using v^2-u^2=2aS
And S=9/2a. (from (i))
u= 4. (given)
v^2-(4)^2=2aS
v^2-16= 2a*9/2a
Cancelling 2a and 1/2a
v^2-16=9
v^2=25
v=5m/s. ANS.