Question

please answer it fast...

if any ace, genius or moderators are present. please help me.

Answer 1

acceleration =
$\frac{v - u}{t}$
where v is final velocity, u is initial velocity.
First convert 54km/hr to m/s
so
54 × 5/18 = 15m/s
now final velocity is 15
initial velocity is 0
time = 2 min = 120 sec(time should always be in second and speed always in metre)
so by applying the formula we have
a =
$\frac{15 - 0}{120} = \frac{15}{120} = 0.125$
acceleration is 0.125m/s^2

Now distance (s ) = ut + 1/2at^2
so by applying formula.
$0 \times 120 + \frac{1}{2} \times 0.125 \times 120 \times 120 \\ = 0 + 900 = 900$
So acceleration is 0.125m/s^2
distance travelled during acceleration is 900m

Hope it helps