Question

Please answer it fast with method I need your help ​

Answer 1

$\blacksquare\:\:\underline{\underline{\footnotesize{\text{SolutioN}}}}$

$=\footnotesize{x^3+6x^2+11x+6}$

$=\footnotesize{x^3+x^2+5x^2+5x+6x+6}$

$=\footnotesize{x^2(x+1)+5x(x+1)+6(x+1)}$

$=\footnotesize{(x+1)(x^2+5x+6)}$

$=\footnotesize{(x+1)(x^2+3x+2x+6)}$

$=\footnotesize{\text{(x+1)[x(x+3)+2(x+3)]}}$

$=\footnotesize{\text{(x+1)[(x+3)(x+2)]}}$

$=\footnotesize{\text{(x+1)(x+2)(x+3)}}$

$\therefore\:\:\footnotesize{x^3+6x^2+11x+6=(x+1)(x+2)(x+3)}$

Answer 2

$\rule{200}4$

$\huge\tt{TO~FACTORISE:}$

• x³ + 6x² + 11x + 6

$\rule{200}4$

$\huge\tt{FACTORING:}$

↪x³ + 6x² + 11x + 6

↪x³ + x² + 5x² + 5x + 6x + 6

↪x²(x+1) + 5x(x+1) + 6(x+1)

↪(x+1) (x² + 5x + 6)

↪(x+1)[x (x+3)+2(x+3)]

↪(x+1)[(x+3)(x+2)]

↪(x+1)(x+2)(x+3)

$\rule{200}4$