Question

Please answer it fastly

Answer 1

Answer:

your answer is 2 is correct

Answer 2

sin∅ + cos ∅=√2

asin∅+bcos∅=c

.

$divide \: equation \: by \: \sqrt{a ^{2} + b ^{2} }$

dividing with √2 both sides

1/√2sin∅ + 1/√2 cos∅=1 ........(1)

sin(45°)=cos(45°)=1/√2

(1).... becomes cos (45°)sin(∅) + sin(45)cos(∅)=sin(90°). [ because sin(90°)=1]

CosASinB + CosBsinA=Sin(A+B)

so above equation becomes

sin(45 +∅)= sin(90)

45+ ∅=90

∅=45

From question b=√2(sin∅+cos∅)/sin∅cos∅

here sin∅=cos∅=sin(45)=cos(45)=1/√2

b=√2( 1/√2 +1/√2 )/[1/√2×1/√2]

b=√2(2/√2)/[1/2]=2/[1/2]=4