please answer it
Find the value of K for which the quadratic equation 2Kx^2 - 2(1+2k)x + (3+2k) = 0 has equal root ....
vivekpnair11479:
is it 1\10
no its 1/2
ok
....
tumhara , A=?,B=?,C=?.................QUADRATIC FORMULA ME??????
Answers
Answered by
7
Heya
______________________________
For equal roots Descrimnant = 0
Descrimnant of given quadratic equation is =
( -2 × ( 1 + 2k ) )² - 4 ( 3 + 2k ) × ( 2k )
=>
4 ( 1 + 2k )² - 4 ( 3 + 2k ) × 2k = 0
=>
4{(1 + 2k)² - (3 + 2k)× 2k} =0
=>
( 1 + 2k )² - 2k × (3 + 2k) = 0
=>
1 + 4k² +4k - 6k - 4k² = 0
=>
1 - 2k = 0
=>
1 = 2k
=>
k = 1/2
______________________________
For equal roots Descrimnant = 0
Descrimnant of given quadratic equation is =
( -2 × ( 1 + 2k ) )² - 4 ( 3 + 2k ) × ( 2k )
=>
4 ( 1 + 2k )² - 4 ( 3 + 2k ) × 2k = 0
=>
4{(1 + 2k)² - (3 + 2k)× 2k} =0
=>
( 1 + 2k )² - 2k × (3 + 2k) = 0
=>
1 + 4k² +4k - 6k - 4k² = 0
=>
1 - 2k = 0
=>
1 = 2k
=>
k = 1/2
10
kyo
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why
ist answer my question
do u wana to become a doctor
yaa
that's y u are asking such question......like this .... Me. take 4 as L.C.M you ::. mention na
??
Nothing.....Have a nyc tym ...bye
Answered by
7
heya...
✔here is ua answer in attachment.
hope it helps..!!❤
Attachments:
Nyc1 dear.
thx
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