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Answers
Answer:
40cm. answer this wright I think
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Area of polygon, ABCDEF is 4700 cm^2cm
2
.
Given
To find the area of the polygon, ABCDEF.
Given sides,
FP = 10 cm FQ = 20 cm
FR = 50 cm FS = 60 cm
FC = 100 cm
From the figure,
In ΔFEP,
Area of triangle = 1/2 × b × h
h = 40 cm ; b = 10 cm
= 1/2 × 10 × 40
= 400/2
= 200 cm^2cm
2
In ΔFQA,
Area of triangle = 1/2 × b × h
h = 20 cm ; b = 20 cm
= 1/2 × 20 × 20
= 400/2
= 200 cm^2cm
2
In ΔBSC,
Area of triangle = 1/2 × b × h
h = 40 cm ; b = 10 cm
= 1/2 × 10 × 40
= 1/2 × 400
= 200 cm^2cm
2
In ΔDRC,
Area of triangle = 1/2 × b × h
h = 60 cm ; b = ( FC - FR ) = 100 - 50 = 50 cm
= 1/2 × 50 × 60
= 1/2 × 3000
= 1500 cm^2cm
2
In trapezium EPRD,
Area of trapezium = 1/2 ( b_1 + b_2b
1
+b
2
) × h
h = ( FR - FP ) = 50 - 10 = 40
b_1b
1
= 40 cm ; b_2b
2
= 60 cm
= 1/2 ( 40 + 60 ) × 40
= 1/2 ( 100 × 40 )
= 1/2 × 4000
= 2000 cm^2cm
2
In trapezium AQSB,
Area of trapezium = 1/2 ( b_1 + b_2b
1
+b
2
) × h
h = ( FS - FQ ) = 50 - 10 = 40 cm ;
b_1b
1
= 20 cm ; b_2b
2
= 10 cm
= 1/2 ( 20 + 10 ) × ( 40 )
= 1/2 ( 30 × 40 )
= 1/2 × 1200
= 600 cm^2cm
2
Area of polygon, ABCDEF = Area of ΔFEP + Area of ΔFQA + Area of ΔBSC +
Area of ΔDRC + Area of trapezium EPRD +
Area of trapezium AQSB
= 200 cm^2cm
2
+ 200 cm^2cm
2
+ 200 cm^2cm
2
+ 1500 cm^2cm
2
+
2000 cm^2cm
2
+ 600 cm^2cm
2
= 4700 cm^2cm
2
.
Therefore, area of polygon = 4700 cm^2cm
2